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Please help me with this program

Program Specifications: That slacker programmer, Nadha Skolar, is at it again. The company where he used to work has uncovered yet another program of his that does not work properly – it is riddled with syntax, logic errors and poor style. You have again been asked to fix the program so that it runs properly and uses good style. Be sure to change the information in the comment heading at the top of the program prior to submitting for scoring.

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The program Nadha Skolar wrote is supposed to test various methods that compute summation formulas using loops to see if the resulting summation from the loop is equivalent to the summation’s “short-cut” formula. For example the summation ∑c from 1 to n where c is a constant would be programmed using a method containing a loop that computes c + c + c + c + … + c (n times). The equivalent “short-cut” for this formula would be c * n.

Nadha Skolar was supposed to write and test three such summation formulas to determine if the methods and corresponding loops correctly computed the summation. In addition to the summation example above, the other two summation formulas that were to be written and checked are:

  • The summation ∑i from 1 to n. This should be equivalent to n(n+1) / 2
  • The summation ∑i2 from 1 to n. This should be equivalent to n(n+1)(2n+1)/6

Sample Execution:

———- TEST 1 ———-
Enter the value for the constant “C”

Summation of a constant 4 from 1 to 50
Loop Equation
—- ——–
200 200

———- TEST 2 ———-
Summation of i from 1 to 50

Loop Equation
—- ——–
1275 1275

———- TEST 3 ———-
Summation of i squared from 1 to 50

Loop Equation
—- ——–
42925 42925

/* *******************************************************************

Debug the file and highlight the parts you debugged, explain why

******************************************************************** */

import java.util.Scanner;

/* Name:

VUnetID: skolarna


Honor statement: I have not given or received unauthorized aid on this assignment. Can you tell?

Date: 01/25/2017


public class Summation {

public final int N = 50; //constant

public static void main(String[] args) {

one(); //summation of constant c

two(); //summation i 1 to N

three(); //summation of i squared 1 to N


// ************************************************

// DESCRIPTION – performs a summation of a constant c

// ************************************************

public static void one() {

int sum=0; //initialize

//print headings

System.out.println(“———- TEST 2 ———-“);

Scanner keyboard = new Scanner(;

//prompt for constant c

System.out.println(“Enter the value for the constant “C”);

c = keyboard.nextInt();

//print column headings


System.out.println(“Summation of a constant ” + c + ” from 1 to ” + N);

System.out.println(“Loop” + ” ” + “Equation”)

System.out.println(“—-” + ” ” + “——–“);

//loop to compute summation of constant c

for (int i = 0; i <= N; i++) {

sum =+c;


//print results

System.out.println(sum + ” ” + sum * N);



// ************************************************

// DESCRIPTION – computes the summation of i from to N

// ************************************************

public static void two() {

System.out.println(“———- TEST 1 ———-“);

System.out.println(“Summation of i from 1 to ” + n);


System.out.println(“Loop” + ” ”

+ “Equation”);

System.out.println(“—-” + ” ” + “——–“);

for (int i = 0; i < N; i++) { int sum = 0;

sum += N;

System.out.println(sum + ” ” + N * (N + 1) / 2);


// ************************************************

// DESCRIPTION – performs a summation of a i squared

// ************************************************

public static void Three() {

int sum = 0; //initialize

//print headings

System.out.print(“———- TEST 3 ———-“);

System.out.println(“Summation of i squared from 1 to ” + N);


System.out.println(“Loop” + ” ” + “Equation”);

System.out.println(“—-” + ” ” + “——–“);

//loop to compute summation of i squared 1 to N

for (int i = N; i >= 0; i++) {

sum += i * i;


//print loop result and the result of the summation formula

System.out.println(sum + ” ” + N * (N + 1) * (2 * N) / 6);


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